2x^2+27x+91=0

Solution for 2x^2+27x+91=0 equation:

2x^2+27x+91=0

a = 2; b = 27; c = +91;
Δ = b2-4ac
Δ = 272-4·2·91
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-1}{2*2}=\frac{-28}{4}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+1}{2*2}=\frac{-26}{4}
=-6+1/2
$